C++相对C语言的改进就是引入了面向对象操作，支持函数重载、类继承、模板、异常处理等等概念。在C++中，一般用函数模板来操作释放指针，这样的好处是可以进行类型检查。
view plai
// 删除数组
template
inline void safe_delete(T *&target) {
if (nullptr != target) {
delete target;
target = nullptr;
}
}
// 删除数组指针
template
inline void safe_delete_arr(T *&target) {
if (nullptr != target) {
delete[] target;
target = nullptr;
}
}
三、void *指针问题
在C、C++ 中，void * 指针可以转换为任意类型的指针类型，在删除void*指针时编译器往往会发出如下警告
warning: deleting 'void*' is undefined [enabled by default]
翻译：警告：删除“void *”指针可能引发未知情况（默认打开警告）
永远记住，在C、C++开发中绝对不能忽视警告，一定要重视警告，最好消除警告。有些警告无关紧要，有些警告却是bug的根源；删除void *指针的警告就属于后面一种情况，可能引起严重的bug而且难以发现：
1. 使用delete pointer; 释放void指针void *，系统会以释放普通指针（char, short, int, long, long long）的方式来释放void *指向的内存空间；
2. 如果void *指向一个数组指针，那么由于释放指针时用了delete pointer从而导致内存泄漏，释放指针正确做法是delete[] pointer;
3. 如果void *指向一个class类，那么系统由于认为void *指向一个普通的内存空间，所以释放指针时系统class的析构函数不会调用；
释放void *的解决方案：将void *转换为原来类型的指针，然后再调用delete释放指针，如果原来的指针是数组指针，那么必须使用delete []删除指向的内存空间。
在C++中我们可以使用模板定义内联函数：
template
inline void safe_delete_void_ptr(void *&target) {
if (nullptr != target) {
T* temp = static_cast
delete temp;
temp = nullptr;
target = nullptr;
}
}
调用方法
view plain
cop
int *psample = new int(100);
safe_delete_void_ptr
利用模板实例化参数统一简化过程。
测试代码
safe_delete_demo.cpp
#include
#include
#include
#include
template
inline void safe_delete(T *&target) {
if (nullptr != target) {
delete target;
target = nullptr;
}
}
template
inline void safe_delete_void_ptr(void *&target) {
if (nullptr != target) {
T* temp = static_cast
delete temp;
temp = nullptr;
target = nullptr;
}
}
class A {
public:
A(std::string name) {
this->name = name;
};
virtual ~A() {
std::cout<<"base class A's destructor"<<", name: "< }; public: std::string name; }; class AChild: public A { public: AChild(std::string name, std::string school) : A(name){ this->school = school; }; ~AChild() { std::cout<<"child class AChild's destructor"<<", name: "< <<", school: "< }; public: std::string school; }; int main(int argc, char *argv[]) { // 测试safe_delete释放普通类指针 std::cout<<"safe_delete pointer of type AChild"< AChild *a1 = new AChild("jacky", "Shenzhen University"); safe_delete(a1); std::cout< // 测试safe_delete释放void*指针 std::cout<<"safe_delete pointer of type void *"< void *vp = new AChild("Polyn", "Southern University of Science and Technology"); safe_delete(vp); std::cout< // 测试safe_delete_void_ptr释放模板实例化为基类的void*指针 std::cout<<"safe_delete_void_ptr pointer of type void * ==> A *"< void *vpA = new AChild("Heral", "Renmin University of China"); safe_delete_void_ptr(vpA); std::cout< // 测试safe_delete_void_ptr释放模板实例化为子类的void*指针 std::cout<<"safe_delete_void_ptr pointer of type void * ==> AChild *"< void *vpAChild = new AChild("pevly", "Southeast University"); safe_delete_void_ptr return 0; } 编译及运行 $ g++ -std=c++11 safe_delete_demo.cpp safe_delete_demo.cpp: In instantiation of 'void safe_delete(T*&) [with T = void]': safe_delete_demo.cpp:59:16: required from here safe_delete_demo.cpp:9:9: warning: deleting 'void*' is undefined [enabled by default] delete target; $ ./a.out safe_delete pointer of type AChild child class AChild's destructor, name: jacky, school: Shenzhen University base class A's destructor, name: jacky safe_delete pointer of type void * safe_delete_void_ptr pointer of type void * ==> A * child class AChild's destructor, name: Heral, school: Renmin University of China base class A's destructor, name: Heral safe_delete_void_ptr pointer of type void * ==> AChild * child class AChild's destructor, name: pevly, school: Southeast University base class A's destructor, name: pevly 通过测试用例我们可以看出。 1. 使用safe_delete释放明确的类会自动触发析构函数（如果析构函数为虚函数，那么先调用子类的析构函数再调用子类的直接基类的析构函数）； 2. 使用safe_delete释放void*指针指向的类时，不会触发对应类的析构函数； 3. 如果使用safe_delete_void_ptr内联函数释放void*指针，那么由于在释放指针前，函数会将void*指针转换为特定类型的函数指针，所以最终能够触发调用析构函数，并且不影响虚类的释放行为。 本文转自: http://blog.csdn.net/sweettool/article/details/77688337